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X^2-6X-4X+17=0
We add all the numbers together, and all the variables
X^2-10X+17=0
a = 1; b = -10; c = +17;
Δ = b2-4ac
Δ = -102-4·1·17
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{2}}{2*1}=\frac{10-4\sqrt{2}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{2}}{2*1}=\frac{10+4\sqrt{2}}{2} $
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